C interview question 8

What will be the output of the given code?

#include <stdio.h>

int main(void) {
 
 float a = 3.14;
 
 printf("%f",a%3);
 
 return 0;
}

Ans: Error

Reason: 

The modulus operator requires int type of data for it's operation.

Here we are giving one float data and other is integer data so the output will be an error.

C interview question 7

What will be the output of the given code?

#include <stdio.h>

int main(void)

{

char c='D';

printf ("%c",c+1);

return 0;

}

Output:
E
Reason:
Char c will store the ASCII value of D
When you print C+1 the next char to D that is E is being printed in the output.

C interview question 6

What will be the output of the given code?

void main()
{
int i=1;
i=!i>2;
printf ("i=%d",i);
}
Ans: 0


Reason:
!1 will be 0 [Because of precedence of operator, ! Operator has more precedence than the > operator]
0 is compared with 2
Condition  greater than fails
So the value of i will be 0

C interview question 5

What will the output of the given code?

#include<stdio.h>

void main ()

{

int a=3;

a = ++a + ++a;

printf ("a=%d",a);

}

Ans:10

Reason:

Here pre-increment operator is used so the value of a is increased to 4 again another pre-increment operator which increases the value of a to 5 , then the value of a is added and assigned to a .

a    =   ++a    +    ++a;

  a=3

 ++a=4

 ++a=5

 a = 5 + 5;

 a = 10;

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C interview question 4

What will be the output of the given code?

#include <stdio.h>

void main()

{
  int a;

  a=9;

  a=printf("Dcoder")+printf("Blog");

  printf("%d",a);

}

Reason:
The return type of printf() is integer and which is being added and assigned to "a" then the value of a is displayed along with the previous outputs printf().

C interview question 3.

What will the output of the given code ?

void main()
{

int a=3;

a=printf ("Dcoder\n");

printf ("%d",a);

}

Output:
Dcoder
7

Reason:

Return type of printf() function is integer .

It prints Dcoder then return value of printf() is assigned to a , then prints the value of a i.e.7
printf () considers "\n" also so the value is 7.

C Interview question.

What is the output ?
void main()
{
Int a=3,b=5;
printf("%d",++(a*b+1));
}

---------------------------------------------------------------------------
Output:
compile time error
Lvalue required.

Reason:
For the increment operator the operands should be always a variable,
Operands cannot be constant or  expression.